F(-5)=3x^2+4x+7

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Solution for F(-5)=3x^2+4x+7 equation: 



(-5)=3F^2+4F+7

We move all terms to the left:

(-5)-(3F^2+4F+7)=0

We add all the numbers together, and all the variables

-(3F^2+4F+7)-5=0

We get rid of parentheses

-3F^2-4F-7-5=0

We add all the numbers together, and all the variables

-3F^2-4F-12=0

a = -3; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·(-3)·(-12)
Δ = -128
Delta is less than zero, so there is no solution for the equation

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